Friday, 11 October 2013

Natural Number

Let m be a natural number with digits consisting entirely of 6's and 0's.
Prove that m is not the square of a natural number.
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Define \(f: \mathbb{R} \rightarrow \mathbb{R}\) by \[f(x)= \begin{cases}(1-\cos x) \sin \left(\frac{1}{x}\right), & x \neq 0 \\ 0, ...