Let \[f(x)=e^{-|x|}, x \in \mathbb{R}\] and \[g(\theta)=\int_{-1}^{1} f\left(\frac{x}{\theta}\right) d x, \theta \neq 0\] Then, \[\lim _{\theta \rightarrow 0} \frac{g(\theta)}{\theta}=\]