Friday, 20 August 2021

For 0≤x<2π, the number of solutions of the equation sin2⁡x+2cos2⁡x+3sin⁡xcos⁡x=0 is
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Define f:R→R by \[f(x)= \begin{cases}(1-\cos x) \sin \left(\frac{1}{x}\right), & x \neq 0 \ 0, ...