Friday, 20 August 2021

Let f:R[0,) be a continuous function such that f(x+y)=f(x)f(y) for all x,yR. Suppose that f is differentiable at x=1 and df(x)dx|x=1=2 Then, the value of f(1)logef(1) is

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Define f:RR by \[f(x)= \begin{cases}(1-\cos x) \sin \left(\frac{1}{x}\right), & x \neq 0 \ 0, ...