Wednesday, 18 August 2021

Consider the following two subsets of C : A={1z:|z|=2} and B={1z:|z1|=2} .  Then (a) A is a circle, but B is not a circle. (b) B is a circle, but A is not a circle. (c) A and B are both circles. (d) Neither A nor B is a circle.

No comments:

Post a Comment

Define f:RR by \[f(x)= \begin{cases}(1-\cos x) \sin \left(\frac{1}{x}\right), & x \neq 0 \ 0, ...