Wednesday 18 August 2021
Consider the following two subsets of \(\mathbb{C}\) :
\[A=\left\{\frac{1}{z}:|z|=2\right\} \text { and } B=\left\{\frac{1}{z}:|z-1|=2\right\} \text { . }\]
Then \(\qquad\)
(a) \(A\) is a circle, but \(B\) is not a circle.
\(\qquad\)
(b) \(B\) is a circle, but \(A\) is not a circle.
\(\qquad\qquad\)
(c) \(A\) and \(B\) are both circles.
\(\qquad\qquad\quad\)
(d) Neither \(A\) nor \(B\) is a circle.
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